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WAEC WASSCE 2017

WAEC Biology 2017 past questions

6 objective questions from the 2017 WAEC Biology paper. Answer each one, then reveal the answer and explanation.

All WAEC Biology past questions

  1. Question 1

    Transport

    Which pigment in red blood cells carries oxygen?

    1. Option A: Haemoglobin
    2. Option B: Chlorophyll
    3. Option C: Melanin
    4. Option D: Plasma
    Show the answer to question 1

    Answer: A, Haemoglobin

    Haemoglobin binds oxygen.

  2. Question 2

    Cell biology

    The plant cell wall is made mainly of

    1. Option A: chitin
    2. Option B: starch
    3. Option C: protein
    4. Option D: cellulose
    Show the answer to question 2

    Answer: D, cellulose

    Plant cell walls are made of cellulose.

  3. Question 3

    Genetics

    In pea plants, the allele for tall (T) is dominant over the allele for short (t). What is the expected phenotypic ratio of the offspring of a cross between TT and tt parents?

    1. Option A: 3 tall : 1 short
    2. Option B: All tall
    3. Option C: 1 tall : 1 short
    4. Option D: All short
    Show the answer to question 3

    Answer: B, All tall

    TT × tt gives only Tt offspring, all showing tall.

  4. Question 4

    Classification

    From the list below, select the animal that is a bird.

    1. Option A: whale
    2. Option B: tortoise
    3. Option C: hen
    4. Option D: newt
    Show the answer to question 4

    Answer: C, hen

    The hen is a bird (class Aves).

  5. Question 5

    Ecology

    Which bacterium fixes nitrogen in the root nodules of legumes?

    1. Option A: Rhizobium
    2. Option B: Nitrosomonas
    3. Option C: Nitrobacter
    4. Option D: Clostridium
    Show the answer to question 5

    Answer: A, Rhizobium

    Rhizobium lives in legume root nodules.

  6. Question 6

    Genetics

    In humans, the allele for normal pigmentation (A) is dominant over the allele for albinism (a). What is the genotypic ratio of the offspring of a cross between two Aa parents?

    1. Option A: 3 AA : 1 aa
    2. Option B: 1 AA : 2 Aa : 1 aa
    3. Option C: 1 AA : 1 aa
    4. Option D: 2 AA : 1 Aa : 1 aa
    Show the answer to question 6

    Answer: B, 1 AA : 2 Aa : 1 aa

    Aa × Aa gives AA, Aa, Aa, and aa: a 1 : 2 : 1 genotypic ratio.

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